
At sunrise, Janet leaves her home (A) and walks towards Marge's home (B) at a constant speed and Marge
leaves her home (B) and walks towards Janet's home (A) also at a constant speed. They meet (at C) at noon
and continue without stopping. Janet arrives at Marge's home at 4:00 p.m. and Marge arrives at Janet's
home at 9:00 p.m. At what time was sunrise?
HINT: Use
x to represent the number of hours from sunrise to noon,
j to represent Janet's speed,
m to represent Marge's speed,
and
AC and
BC to represent the distance between
A and
C, and
B and
C respectively.
ANSWER:
6:00 a.m.
EXPLANATION: Let's use
x to represent the number of hours from sunrise
to noon,
j to represent Janet's speed,
m to represent Marge's speed,
and
AC and
BC to represent the distance between
A and
C, and
B and
C respectively.
Use the formula
Speed = Distance / Time to obtain the speed of Janet and Marge using what is
known about the journey between
A and
C and then do the same for the
journey between
B and
C.
Journey between A and C:
j = AC/x
m = AC/9 → AC = 9m
So: j = 9m/x
(expression 1)
Journey between B and C:
j = BC/4
m = BC/x → BC = (x × m)
So: j = (x × m)/4
(expression 2)
Since the first and second expression equal
j, we can set them equal to each other.
9m/x = (x × m)/4
9/x = x/4
x² = 9 × 4
x = 6 hours before noon, so 6:00 a.m.
Do you have a
suggestion for this puzzle (e.g. something that should
be mentioned/clarified in the question or solution, bug, typo, etc.)?